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Physics Chemistry Biology

Class 9th Chapters
1. Matter In Our Surroundings 2. Is Matter Around Us Pure? 3. Atoms And Molecules
4. Structure Of The Atom 5. The Fundamental Unit Of Life 6. Tissues
7. Motion 8. Force And Laws Of Motion 9. Gravitation
10. Work And Energy 11. Sound 12. Improvement In Food Resources



Chapter 3 Atoms And Molecules



Since ancient times, philosophers in India and Greece pondered the nature of matter and its ultimate composition. Around 500 BC, Indian philosopher Maharishi Kanad proposed that matter (padarth) could be endlessly divided into smaller particles, eventually reaching a smallest, indivisible particle called Parmanu. Another philosopher, Pakudha Katyayama, added that these fundamental particles usually exist in combined forms, giving rise to various types of matter.

Around the same period in Greece, philosophers like Democritus and Leucippus suggested a similar idea: matter is divisible until a point is reached where the particles can no longer be cut or divided. Democritus named these ultimate, indivisible particles atoms (from the Greek word 'atomos', meaning 'uncuttable' or 'indivisible'). These early ideas were philosophical speculations, lacking experimental support until much later.

By the late eighteenth century, scientists had distinguished elements from compounds and became interested in understanding how and why elements combine chemically. This led to significant experimental work and the formulation of fundamental laws governing chemical reactions.

Laws Of Chemical Combination

Antoine L. Lavoisier, considered the father of modern chemistry, along with Joseph L. Proust, established two fundamental laws based on experimental observations of chemical reactions. These laws govern how elements combine to form compounds.


Law Of Conservation Of Mass

This law addresses whether the total mass changes during a chemical reaction. Through careful experiments, such as reacting solutions of substances like copper sulphate and sodium carbonate in a sealed flask, it was observed that the total mass of the reactants before the reaction is equal to the total mass of the products after the reaction. The cork on the flask is crucial to ensure that no substances or gases involved in the reaction escape or enter the system, maintaining a closed environment for accurate mass measurement.

Diagram showing a conical flask with an ignition tube suspended inside, containing separate reactant solutions before mixing.

The **Law of Conservation of Mass** states that **mass can neither be created nor destroyed in a chemical reaction**. In other words, the total mass of the substances undergoing a chemical transformation remains constant.


Law Of Constant Proportions

Scientists like Lavoisier and Proust studied the composition of many compounds and consistently found that a pure chemical compound always contains the same elements combined in the same proportion by mass, regardless of its source or method of preparation. This led to the formulation of the **Law of Constant Proportions**, also known as the **Law of Definite Proportions**.

The law states: **In a chemical substance, the elements are always present in definite proportions by mass**.

For example, water ($\text{H}_2\text{O}$) is always formed by the chemical combination of hydrogen and oxygen in a mass ratio of 1:8. If 9 grams of water are decomposed, 1 gram of hydrogen and 8 grams of oxygen are always obtained, regardless of where the water came from. Similarly, ammonia ($\text{NH}_3$) always contains nitrogen and hydrogen in a fixed mass ratio of 14:3.


Dalton's Atomic Theory

The scientific community needed an explanation for these observed laws of chemical combination. John Dalton, a British chemist, provided the first comprehensive theory about the nature of matter, building upon the ancient philosophical idea of atoms. Dalton's **atomic theory**, proposed in 1808, was based on the laws of chemical combination and successfully explained them.

According to Dalton's atomic theory, all matter is made up of very small particles called atoms. The main postulates of his theory are:

  1. All matter is composed of extremely tiny particles called **atoms**, which are the participants in chemical reactions.
  2. Atoms are **indivisible particles** and cannot be created or destroyed during a chemical reaction (explains the Law of Conservation of Mass).
  3. Atoms of a given element are **identical** in mass and chemical properties.
  4. Atoms of different elements have **different** masses and chemical properties.
  5. Atoms combine in the ratio of **small whole numbers** to form compounds (helps explain the Law of Constant Proportions).
  6. The **relative number and kinds of atoms** are constant in a given compound (directly supports the Law of Constant Proportions).

Although later discoveries showed that atoms are indeed divisible and made of subatomic particles (electrons, protons, neutrons), Dalton's theory provided a fundamental framework for understanding chemical reactions and the composition of matter.

Example 1. In a reaction, 5.3 g of sodium carbonate reacted with 6 g of acetic acid. The products were 2.2 g of carbon dioxide, 0.9 g water and 8.2 g of sodium acetate. Show that these observations are in agreement with the law of conservation of mass.

sodium carbonate + acetic acid → sodium acetate + carbon dioxide + water

Answer:

According to the Law of Conservation of Mass, the total mass of reactants must equal the total mass of products.

Total mass of reactants = Mass of sodium carbonate + Mass of acetic acid

Total mass of reactants = 5.3 g + 6 g = 11.3 g

Total mass of products = Mass of sodium acetate + Mass of carbon dioxide + Mass of water

Total mass of products = 8.2 g + 2.2 g + 0.9 g = 11.3 g

Since the total mass of reactants (11.3 g) is equal to the total mass of products (11.3 g), the observations are in agreement with the Law of Conservation of Mass.

Example 2. Hydrogen and oxygen combine in the ratio of 1:8 by mass to form water. What mass of oxygen gas would be required to react completely with 3 g of hydrogen gas?

Answer:

According to the Law of Constant Proportions, hydrogen and oxygen always combine in a fixed mass ratio of 1:8 to form water.

This means 1 g of hydrogen requires 8 g of oxygen to react completely.

Given mass of hydrogen = 3 g.

Since the mass ratio is 1:8, 3 g of hydrogen will require 3 times the mass of oxygen required for 1 g of hydrogen.

Mass of oxygen required = 3 $\times$ 8 g = 24 g.

Therefore, 24 g of oxygen gas would be required to react completely with 3 g of hydrogen gas to form water.



What Is An Atom?

Just as a building is constructed from bricks, or an ant-hill from grains of sand, all matter is ultimately built from fundamental particles called atoms. Atoms are the basic building blocks of all matter, whether it's an element, a compound, or a mixture.


How Big Are Atoms?

Atoms are incredibly tiny. Their size is so small that they are not visible to the naked eye. We cannot even see them with powerful light microscopes. Even stacking millions of atoms would only form a layer as thin as a sheet of paper.

The size of an atom is typically measured by its atomic radius, often expressed in nanometres (nm).

To appreciate the scale, consider these relative sizes:

Size (in m) Example
$10^{-10}$ Atom of hydrogen
$10^{-9}$ Molecule of water
$10^{-8}$ Molecule of haemoglobin
$10^{-4}$ Grain of sand
$10^{-3}$ Ant
$10^{-1}$ Apple

Despite their minuscule size, atoms are the fundamental units that make up everything around us and continuously influence our world. Modern scientific instruments, like scanning tunnelling microscopes, allow us to produce magnified images of surfaces, showing the arrangement of individual atoms.

Scanning Tunneling Microscope image showing atoms arranged on a surface, like silicon.

What Are The Modern Day Symbols Of Atoms Of Different Elements?

To represent elements concisely, scientists use symbols. John Dalton was one of the first to use specific symbols for elements, with each symbol representing one atom of that element.

Examples of Dalton's historical symbols for elements, such as a circle with a dot for hydrogen, a solid circle for carbon, etc.

As more elements were discovered, a more standardized system was needed. J.J. Berzelius suggested using one or two letters from the element's name as its symbol. The modern system, approved by the **International Union of Pure and Applied Chemistry (IUPAC)**, uses this approach.

Rules for writing element symbols:

Each element has a unique name and a unique chemical symbol.

Here are symbols for some common elements:

Element Symbol Element Symbol Element Symbol
AluminiumAlCopperCuNitrogenN
ArgonArFluorineFOxygenO
BariumBaGoldAuPotassiumK
BoronBHydrogenHSiliconSi
BromineBrIodineISilverAg
CalciumCaIronFeSodiumNa
CarbonCLeadPbSulphurS
ChlorineClMagnesiumMgUraniumUranium (U)
CobaltCoNeonNeZincZn

(Note: You don't need to memorise all of these immediately. Familiarity will grow with practice.)


Atomic Mass

Dalton's atomic theory highlighted that each element has a characteristic atomic mass. Since individual atoms are extremely light, determining their absolute mass is very difficult. Scientists therefore decided to determine the relative atomic masses of elements by comparing them to the mass of a standard reference atom.

Initially, 1/16th the mass of a naturally occurring oxygen atom was used as the reference unit because oxygen forms compounds with many elements and this unit often gave atomic masses close to whole numbers.

However, in 1961, the **carbon-12 isotope** was chosen as the universally accepted standard reference. One **atomic mass unit (u)**, also known as a unified mass unit, is defined as exactly one-twelfth ($1/12$th) the mass of one atom of carbon-12. The relative atomic mass of an atom of an element is the average mass of the atom compared to 1/12th the mass of a carbon-12 atom.

Analogy of a fruit seller using a watermelon as a standard to weigh other fruits, representing the concept of relative atomic mass.

This is analogous to a fruit seller using a watermelon divided into 12 equal pieces as a standard unit ("fruit mass unit" or fmu) to weigh other fruits relatively.

Atomic masses of elements are typically listed in atomic mass units (u). For example, the atomic mass of Hydrogen is approximately 1 u, Carbon is 12 u, and Oxygen is 16 u.

Atomic masses of a few common elements:

Element Atomic Mass (u)
Hydrogen1
Carbon12
Nitrogen14
Oxygen16
Sodium23
Magnesium24
Sulphur32
Chlorine35.5
Calcium40

How Do Atoms Exist?

Atoms are highly reactive and for most elements, they cannot exist independently as single atoms under normal conditions. Instead, atoms combine with each other to form larger entities called molecules and ions. These molecules or ions then aggregate in vast numbers to form the matter that we can observe and interact with (solids, liquids, gases).

Question 1. Define the atomic mass unit.

Answer:

One atomic mass unit (u) is a mass unit equal to exactly one-twelfth (1/12th) the mass of one atom of carbon-12 isotope. It is used as the standard reference for measuring the relative masses of atoms and molecules.

Question 2. Why is it not possible to see an atom with naked eyes?

Answer:

Atoms are extremely small particles, with radii typically around $10^{-10}$ metres. Their size is far below the resolution limit of the human eye and even standard light microscopes. Special instruments like scanning tunnelling microscopes are required to visualize individual atoms.



What Is A Molecule?

A molecule is generally defined as a group of two or more atoms that are held together by chemical bonds (attractive forces). A molecule is the smallest particle of an element or a compound that is capable of independent existence under ordinary conditions and exhibits all the properties of that substance.

Molecules can be formed by atoms of the same element or by atoms of different elements combining together.


Molecules Of Elements

The molecules of an element are made up of only one type of atom. The number of atoms that constitute a molecule of an element is called its **atomicity**.

Elements that are metals (like iron, copper, gold) and some non-metals like carbon do not exist as simple, discrete molecules in the solid state. Instead, they form large structures where a vast and indefinite number of atoms are bonded together.

Atomicity of some elements:

Type of Element Name Atomicity
Non-MetalArgonMonoatomic (1)
Non-MetalHeliumMonoatomic (1)
Non-MetalOxygenDiatomic (2)
Non-MetalHydrogenDiatomic (2)
Non-MetalNitrogenDiatomic (2)
Non-MetalChlorineDiatomic (2)
Non-MetalPhosphorusTetra-atomic (4)
Non-MetalSulphurPoly-atomic (>4, commonly 8)

Molecules Of Compounds

Molecules of compounds are formed when atoms of **different elements** combine chemically in **fixed proportions**. These molecules represent the smallest unit of the compound that retains its chemical properties.

Examples of molecules of compounds:

Compound Combining Elements Ratio by Mass
Water ($\text{H}_2\text{O}$)Hydrogen, Oxygen1:8
Ammonia ($\text{NH}_3$)Nitrogen, Hydrogen14:3
Carbon dioxide ($\text{CO}_2$)Carbon, Oxygen3:8

We can determine the ratio by the *number* of atoms of each element in a compound molecule using the mass ratio and the atomic masses of the elements (Activity 3.2 from the text). For water ($\text{H}_2\text{O}$):

Given mass ratio H:O = 1:8

Atomic mass of H = 1 u, Atomic mass of O = 16 u

Ratio by number of atoms = $\frac{\text{Mass ratio of H}}{\text{Atomic mass of H}} : \frac{\text{Mass ratio of O}}{\text{Atomic mass of O}}$

Ratio by number of atoms = $\frac{1}{1} : \frac{8}{16}$

Ratio by number of atoms = $1 : \frac{1}{2}$

To get a whole number ratio, multiply by 2:

Ratio by number of atoms H:O = $1 \times 2 : \frac{1}{2} \times 2 = 2 : 1$

This confirms the formula $\text{H}_2\text{O}$, indicating two hydrogen atoms and one oxygen atom per molecule.


What Is An Ion?

Some compounds, particularly those formed between metals and non-metals, consist of **charged species** called ions. Unlike molecules which are neutral, ions are atoms or groups of atoms that have gained or lost electrons, resulting in a net electrical charge.

Ions can be formed from a single atom (like $\text{Na}^+$ or $\text{Cl}^-$) or from a group of atoms bonded together that collectively carry a charge. A group of atoms carrying a net charge is called a **polyatomic ion**.

Examples of polyatomic ions: Ammonium ion ($\text{NH}_4^+$), Hydroxide ion ($\text{OH}^-$), Carbonate ion ($\text{CO}_3^{2-}$), Sulphate ion ($\text{SO}_4^{2-}$), Phosphate ion ($\text{PO}_4^{3-}$).

Ionic compounds, like sodium chloride (NaCl), are made up of a collection of positively charged ions ($\text{Na}^+$) and negatively charged ions ($\text{Cl}^-$) held together by strong electrostatic forces. The total positive charge balances the total negative charge, making the overall compound electrically neutral.

Names and symbols of some common ions:

Valency Name of ion Symbol Non-metallic element Symbol Polyatomic ions Symbol
1 SodiumNa⁺ HydrogenH⁺ (Hydride H⁻) AmmoniumNH₄⁺
PotassiumK⁺ ChlorideCl⁻ HydroxideOH⁻
SilverAg⁺ BromideBr⁻ NitrateNO₃⁻
Copper (I)*Cu⁺ IodideI⁻ Hydrogen carbonateHCO₃⁻
2 MagnesiumMg²⁺ OxideO²⁻ CarbonateCO₃²⁻
CalciumCa²⁺ SulphideS²⁻ SulphiteSO₃²⁻
ZincZn²⁺ SulphateSO₄²⁻
Iron (II)*Fe²⁺
Copper (II)*Cu²⁺
3 AluminiumAl³⁺ NitrideN³⁻ PhosphatePO₄³⁻
Iron (III)*Fe³⁺

*Some elements like copper and iron can show more than one valency. The Roman numeral in parentheses indicates their specific valency in that context.



Writing Chemical Formulae

The **chemical formula** of a compound is a symbolic representation that shows the types of elements present and the relative number of atoms of each element in one molecule or formula unit of the compound. Writing correct chemical formulae requires knowledge of the symbols of elements and their combining capacity.

The **valency** of an element is its combining power or capacity – it indicates how many atoms of another element it can combine with. Valency can be thought of as the 'arms' of an atom that connect to the 'arms' of other atoms. For example, if an octopus has 8 arms (valency 8) and humans have 2 arms (valency 2), one octopus could theoretically hold 4 humans if all arms are engaged, leading to a combination with a formula like $\text{OH}_4$ (where O represents octopus and H represents human). The subscript number shows the quantity of the second entity.


Formulae Of Simple Compounds

Compounds made up of two different elements are called **binary compounds**. We can write their formulae using the concept of valency and a method often called the 'criss-cross' method.

General steps for writing chemical formulae:

  1. Write the symbols of the constituent elements. For ionic compounds (metal + non-metal), write the metal symbol (cation) first, followed by the non-metal symbol (anion).
  2. Write the valency (or charge) of each element/ion above or below its symbol.
  3. Cross-over the valencies (ignore the sign for ions, just use the magnitude). This means the valency of the first element becomes the subscript for the second, and the valency of the second becomes the subscript for the first.
  4. Simplify the subscripts to the smallest whole-number ratio if possible.

Examples of writing formulae:

1. **Formula of Hydrogen Chloride**

Elements: Hydrogen ($\text{H}$), Chlorine ($\text{Cl}$)

Valency: H = 1, Cl = 1

Criss-cross: $\text{H}_1\text{Cl}_1$

Simplified: HCl

Formula: HCl

2. **Formula of Hydrogen Sulphide**

Elements: Hydrogen ($\text{H}$), Sulphur ($\text{S}$)

Valency: H = 1, S = 2

Criss-cross: $\text{H}_2\text{S}_1$

Simplified: $\text{H}_2\text{S}$

Formula: $\text{H}_2\text{S}$

3. **Formula of Carbon Tetrachloride**

Elements: Carbon ($\text{C}$), Chlorine ($\text{Cl}$)

Valency: C = 4, Cl = 1

Criss-cross: $\text{C}_1\text{Cl}_4$

Simplified: $\text{CCl}_4$

Formula: $\text{CCl}_4$

4. **Formula of Magnesium Chloride** (Ionic Compound)

Ions: Magnesium ion ($\text{Mg}^{2+}$), Chloride ion ($\text{Cl}^-$)

Charge magnitude: Mg = 2, Cl = 1

Criss-cross: $\text{Mg}_1\text{Cl}_2$

Simplified: $\text{MgCl}_2$

Formula: $\text{MgCl}_2$

This means one magnesium ion combines with two chloride ions to form a neutral compound. The charges must balance: $(+2) + 2 \times (-1) = 0$.

When dealing with **polyatomic ions**, special rules apply:

Examples with polyatomic ions:

(a) **Formula for Aluminium Oxide** (Ionic)

Ions: Aluminium ion ($\text{Al}^{3+}$), Oxide ion ($\text{O}^{2-}$)

Charge magnitude: Al = 3, O = 2

Criss-cross: $\text{Al}_2\text{O}_3$

Formula: $\text{Al}_2\text{O}_3$

Charges balance: $2 \times (+3) + 3 \times (-2) = +6 - 6 = 0$.

(b) **Formula for Calcium Oxide** (Ionic)

Ions: Calcium ion ($\text{Ca}^{2+}$), Oxide ion ($\text{O}^{2-}$)

Charge magnitude: Ca = 2, O = 2

Criss-cross: $\text{Ca}_2\text{O}_2$

Simplified (divide subscripts by 2): $\text{Ca}_1\text{O}_1$

Formula: CaO

(c) **Formula of Sodium Nitrate** (Ionic, with polyatomic ion)

Ions: Sodium ion ($\text{Na}^{+}$), Nitrate ion ($\text{NO}_3^{-}$)

Charge magnitude: Na = 1, $\text{NO}_3$ = 1

Criss-cross: $\text{Na}_1(\text{NO}_3)_1$

Simplified (no brackets needed as subscript is 1): $\text{NaNO}_3$

Formula: $\text{NaNO}_3$

(d) **Formula of Calcium Hydroxide** (Ionic, with polyatomic ion)

Ions: Calcium ion ($\text{Ca}^{2+}$), Hydroxide ion ($\text{OH}^{-}$)

Charge magnitude: Ca = 2, OH = 1

Criss-cross: $\text{Ca}_1(\text{OH})_2$

Simplified (brackets needed as subscript is 2): $\text{Ca(OH)}_2$

Formula: $\text{Ca(OH)}_2$. This indicates one calcium ion for every two hydroxide ions. The bracket around OH shows that the subscript 2 applies to both oxygen and hydrogen atoms within the hydroxide group.

(e) **Formula of Sodium Carbonate** (Ionic, with polyatomic ion)

Ions: Sodium ion ($\text{Na}^{+}$), Carbonate ion ($\text{CO}_3^{2-}$)

Charge magnitude: Na = 1, $\text{CO}_3$ = 2

Criss-cross: $\text{Na}_2(\text{CO}_3)_1$

Simplified (no brackets needed as subscript is 1): $\text{Na}_2\text{CO}_3$

Formula: $\text{Na}_2\text{CO}_3$

(f) **Formula of Ammonium Sulphate** (Ionic, with polyatomic ions)

Ions: Ammonium ion ($\text{NH}_4^{+}$), Sulphate ion ($\text{SO}_4^{2-}$)

Charge magnitude: $\text{NH}_4$ = 1, $\text{SO}_4$ = 2

Criss-cross: $(\text{NH}_4)_2(\text{SO}_4)_1$

Simplified (brackets needed for $\text{NH}_4$ as subscript is 2; no brackets for $\text{SO}_4$ as subscript is 1): $\text{(NH}_4\text{)}_2\text{SO}_4$

Formula: $\text{(NH}_4\text{)}_2\text{SO}_4$



Molecular Mass

The concept of atomic mass can be extended to determine the mass of molecules and ionic compounds.


Molecular Mass

The **molecular mass** of a substance is the sum of the atomic masses of all the atoms present in one molecule of that substance. It represents the relative mass of a molecule compared to the carbon-12 standard, and is expressed in atomic mass units (u). To calculate the molecular mass, multiply the atomic mass of each element by the number of atoms of that element in the molecule and then add up these values for all elements in the molecule.

Example 3.1. (a) Calculate the relative molecular mass of water ($\text{H}_2\text{O}$). (b) Calculate the molecular mass of $\text{HNO}_3$.

Answer:

(a) Molecular formula of water is $\text{H}_2\text{O}$. It contains 2 hydrogen atoms and 1 oxygen atom.

Atomic mass of Hydrogen (H) = 1 u

Atomic mass of Oxygen (O) = 16 u

Molecular mass of $\text{H}_2\text{O}$ = (2 $\times$ Atomic mass of H) + (1 $\times$ Atomic mass of O)

Molecular mass of $\text{H}_2\text{O}$ = $(2 \times 1 \text{ u}) + (1 \times 16 \text{ u})$

Molecular mass of $\text{H}_2\text{O}$ = 2 u + 16 u = 18 u

The relative molecular mass of water is 18 u.

(b) Molecular formula of nitric acid is $\text{HNO}_3$. It contains 1 hydrogen atom, 1 nitrogen atom, and 3 oxygen atoms.

Atomic mass of Hydrogen (H) = 1 u

Atomic mass of Nitrogen (N) = 14 u

Atomic mass of Oxygen (O) = 16 u

Molecular mass of $\text{HNO}_3$ = (1 $\times$ Atomic mass of H) + (1 $\times$ Atomic mass of N) + (3 $\times$ Atomic mass of O)

Molecular mass of $\text{HNO}_3$ = $(1 \times 1 \text{ u}) + (1 \times 14 \text{ u}) + (3 \times 16 \text{ u})$

Molecular mass of $\text{HNO}_3$ = 1 u + 14 u + 48 u = 63 u

The molecular mass of nitric acid is 63 u.


Formula Unit Mass

For ionic compounds, which exist as a collection of ions rather than discrete molecules, the term **formula unit mass** is used instead of molecular mass. The formula unit mass is the sum of the atomic masses of all the atoms (which form the ions) in one **formula unit** of the compound. The calculation is done in the same way as molecular mass calculation, but the term 'formula unit mass' is specifically applied to ionic compounds.

For example, the formula unit of sodium chloride is NaCl. Its formula unit mass is calculated by adding the atomic mass of sodium and the atomic mass of chlorine.

Atomic mass of Na = 23 u

Atomic mass of Cl = 35.5 u

Formula unit mass of NaCl = (1 $\times$ Atomic mass of Na) + (1 $\times$ Atomic mass of Cl)

Formula unit mass of NaCl = $(1 \times 23 \text{ u}) + (1 \times 35.5 \text{ u}) = 23 \text{ u} + 35.5 \text{ u} = 58.5 \text{ u}$

Example 3.2. Calculate the formula unit mass of $\text{CaCl}_2$.

Answer:

The formula unit of calcium chloride is $\text{CaCl}_2$. It contains 1 calcium atom and 2 chlorine atoms.

Atomic mass of Calcium (Ca) = 40 u

Atomic mass of Chlorine (Cl) = 35.5 u

Formula unit mass of $\text{CaCl}_2$ = (1 $\times$ Atomic mass of Ca) + (2 $\times$ Atomic mass of Cl)

Formula unit mass of $\text{CaCl}_2$ = $(1 \times 40 \text{ u}) + (2 \times 35.5 \text{ u})$

Formula unit mass of $\text{CaCl}_2$ = 40 u + 71 u = 111 u

The formula unit mass of calcium chloride is 111 u.



Intext Questions



Page No. 27 - 28

Question 1. In a reaction, 5.3 g of sodium carbonate reacted with 6 g of acetic acid. The products were 2.2 g of carbon dioxide, 0.9 g water and 8.2 g of sodium acetate. Show that these observations are in agreement with the law of conservation of mass.

sodium carbonate + acetic acid $ \rightarrow $ sodium acetate + carbon dioxide + water

Answer:

Question 2. Hydrogen and oxygen combine in the ratio of 1:8 by mass to form water. What mass of oxygen gas would be required to react completely with 3 g of hydrogen gas?

Answer:

Question 3. Which postulate of Dalton’s atomic theory is the result of the law of conservation of mass?

Answer:

Question 4. Which postulate of Dalton’s atomic theory can explain the law of definite proportions?

Answer:



Page No. 30

Question 1. Define the atomic mass unit.

Answer:

Question 2. Why is it not possible to see an atom with naked eyes?

Answer:



Page No. 34

Question 1. Write down the formulae of

(i) sodium oxide

(ii) aluminium chloride

(iii) sodium sulphide

(iv) magnesium hydroxide

Answer:

Question 2. Write down the names of compounds represented by the following formulae:

(i) $Al_2(SO_4)_3$

(ii) $CaCl_2$

(iii) $K_2SO_4$

(iv) $KNO_3$

(v) $CaCO_3$

Answer:

Question 3. What is meant by the term chemical formula?

Answer:

Question 4. How many atoms are present in a

(i) $H_2S$ molecule and

(ii) $PO_4^{3-}$ ion?

Answer:



Page No. 35

Question 1. Calculate the molecular masses of $H_2$, $O_2$, $Cl_2$, $CO_2$, $CH_4$, $C_2H_6$, $C_2H_4$, $NH_3$, $CH_3OH$.

Answer:

Question 2. Calculate the formula unit masses of $ZnO$, $Na_2O$, $K_2CO_3$, given atomic masses of $Zn = 65\ u$, $Na = 23\ u$, $K = 39\ u$, $C = 12\ u$, and $O = 16\ u$.

Answer:



Exercises



Question 1. A 0.24 g sample of compound of oxygen and boron was found by analysis to contain 0.096 g of boron and 0.144 g of oxygen. Calculate the percentage composition of the compound by weight.

Answer:

Question 2. When 3.0 g of carbon is burnt in 8.00 g oxygen, 11.00 g of carbon dioxide is produced. What mass of carbon dioxide will be formed when 3.00 g of carbon is burnt in 50.00 g of oxygen? Which law of chemical combination will govern your answer?

Answer:

Question 3. What are polyatomic ions? Give examples.

Answer:

Question 4. Write the chemical formulae of the following.

(a) Magnesium chloride

(b) Calcium oxide

(c) Copper nitrate

(d) Aluminium chloride

(e) Calcium carbonate.

Answer:

Question 5. Give the names of the elements present in the following compounds.

(a) Quick lime

(b) Hydrogen bromide

(c) Baking powder

(d) Potassium sulphate.

Answer:

Question 6. Calculate the molar mass of the following substances.

(a) Ethyne, $C_2H_2$

(b) Sulphur molecule, $S_8$

(c) Phosphorus molecule, $P_4$ (Atomic mass of phosphorus = 31)

(d) Hydrochloric acid, $HCl$

(e) Nitric acid, $HNO_3$

Answer: